(2x-1)(x^2+4x-4)=

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Solution for (2x-1)(x^2+4x-4)= equation: 


Simplifying
(2x + -1)(x2 + 4x + -4) = 0

Reorder the terms:
(-1 + 2x)(x2 + 4x + -4) = 0

Reorder the terms:
(-1 + 2x)(-4 + 4x + x2) = 0

Multiply (-1 + 2x) * (-4 + 4x + x2)
(-1(-4 + 4x + x2) + 2x * (-4 + 4x + x2)) = 0
((-4 * -1 + 4x * -1 + x2 * -1) + 2x * (-4 + 4x + x2)) = 0
((4 + -4x + -1x2) + 2x * (-4 + 4x + x2)) = 0
(4 + -4x + -1x2 + (-4 * 2x + 4x * 2x + x2 * 2x)) = 0
(4 + -4x + -1x2 + (-8x + 8x2 + 2x3)) = 0

Reorder the terms:
(4 + -4x + -8x + -1x2 + 8x2 + 2x3) = 0

Combine like terms: -4x + -8x = -12x
(4 + -12x + -1x2 + 8x2 + 2x3) = 0

Combine like terms: -1x2 + 8x2 = 7x2
(4 + -12x + 7x2 + 2x3) = 0

Solving
4 + -12x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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